FORTRAN statement
c*******  Nmf2 (or hmF2)  for a given longitude sector (e.g.  25 degrees longitude) 
    

    year = 2006    ! event year
    doy_i = 347    ! first day of year of the event
    doy_f = 349    ! last day of year of the event
    lon = 25.  +  2.5     ! one of eight selected longitude slices  (2.5 = (bin size of 5.AN0)/2)

    do idoy =doy_i, doy_f
      do ihr =0,23,1  !! hour
        do imin=0,45,15   !! min , 15 min temporal bin
          do isec =0, 0    !! fixed
            do ilat =1, 36  !! # of 5.AN0 latitude bins 
                write(1,'(5i6,3f10.2)') 
&             year,idoy, ihr, imin, isec, lat(ilat)-2.5,lon-2.5, 
&             NmF2(idoy,ihr,imin+7,isec+30,lat,lon) 
          enddo 
        enddo	
       enddo	
     enddo	
   enddo


where,  lat(ilat) = -95. + 5.*ilat + 2.5   (1 <= ilat <= 36)
ccccc